5p^2+210=65p

Solution for 5p^2+210=65p equation:

5p^2+210=65p

We move all terms to the left:

5p^2+210-(65p)=0

a = 5; b = -65; c = +210;
Δ = b2-4ac
Δ = -652-4·5·210
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-5}{2*5}=\frac{60}{10}
=6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+5}{2*5}=\frac{70}{10}
=7
$